What we like about this task
- Addresses standards: 8.EE.B, MP.1, MP.3, and MP.6
- Presents an unfamiliar problem that students must make sense of (MP.1)
- Keys directly on the meanings of the parameters in a linear equation as found in cluster 8.EE.B
- Involves two basic forms for the equation of a line (not just the form $y=mx+b$ but also the form $ax+by=c$)
In the classroom:
Making the Shifts
How does this task exemplify the instructional Shifts required by CCSSM?
Focus Belongs to the major work of eighth grade Coherence Builds solid foundation for high school algebra Rigor
Conceptual Understanding: primary in this task
Procedural Skill and Fluency: secondary in this task
Application: not targeted in this task
The figure below shows two lines. One is described by the equation $4x-y=c$ and the other by equation $y=2x+d$, for some constants $c$ and $d$. They intersect at the point $(p, q)$.
a. How can you interpret $c$ and $d$ in terms of the graphs of the equations above?
b. Imagine you place the tip of your pencil at point $(p, q)$ and trace line $l$ out of the point with $x$-coordinate $p+2$. Imagine I do the same on line $m$. How much greater would the $y$-coordinate of your ending point be than mine?
Illustrative Mathematics Commentary and Solution
This task requires students to use the fact that on the graph of the linear equation $y=ax+c$, the $y$-coordinate increases by $a$ when $x$ increases by one. Specific values for $c$ and $d$ were left out intentionally to encourage students to use the above fact as opposed to computing the point of intersection $(p, q)$, and then computing respective function values to answer the question.
- If we put the equation $4x-y=c$ in the form $y=4x-c$, we see that the graph has slope $4$. The slope of the graph of $y=2x+d$ is $2$. So the steeper line, $l$, is the one with equation $y=4x-c$, and therefore $-c$ is the $y$-coordinate of the point where $l$ intersects the $y$-axis. The other line, $m$, is the one with equation $y=2x+d$, so $d$ is the $y$-coordinate of the point where $m$ intersects the $y$-axis.
- The line $l$ has slope $4$. So on $l$, each increase of one unit in the $x$-value produces an increase of $4$ units in the $y$-value. Thus an increase of $2$ units in the $x$-value produce an increase of $2⋅4=8$ units in the $y$-value. The line $m$ has slope $2$. So on $L_2$, each increase of $1$ unit in the $x$-value produces an increase of $2$ units in the $y$-value. Thus an increase of $2$ units in the $x$-value produces an increase of $2⋅2=4$ units in the $y$-value. Thus your $y$-value would be $8-4=4$ units larger than my $y$-value.
This task related directly to the cluster heading 8.EE.B, "Understand the connections between proportional relationships, lines, and linear equations." Specifically, for each 1 unit moved horizontally, a point moving along the line $y=ax+b$ moves $a$ units vertically. Notice how this sentence involves a proportional relationship, a line in the plane, and the equation of that line.
This task in itself doesn't build/rely upon procedural skill with equations of lines in the plane, but tasks of that nature are appropriate in grade 8 as well.
For more insight into the expectations for slope and linear equations in grade 8, read pages 10–12 of the progressions document, 6–8 Expressions and Equations.